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Parity decomposition of tree-witness safety (two half-scale problems plus a root condition)

Proved
Erdos195.safe_parity_decomp

by Ethan Cheung Wang · Oct 23, 2026 · Mathlib 0df444a (Lean v4.33.1)

arithmetic-progressionscombinatoricserdos-problems

A tree witness is a function θ:N×Z→{0,1}\theta:\mathbb N\times\mathbb Z\to\{0,1\}θ:N×Z→{0,1} on the nodes (k,r)(k,r)(k,r) of the binary tree of residues. For distinct integers x,yx,yx,y with k=ν2(y−x)k=\nu_2(y-x)k=ν2​(y−x), put x≺θyx\prec_\theta yx≺θ​y iff bitk(x)=1⇔θ(k, x mod 2k)=1\mathrm{bit}_k(x)=1 \Leftrightarrow \theta(k,\,x\bmod 2^k)=1bitk​(x)=1⇔θ(k,xmod2k)=1 (bitk\mathrm{bit}_kbitk​ is the kkk-th two's-complement binary digit). A finite word QQQ of integers is θ\thetaθ-safe if the completion "the letters of QQQ in order, then all remaining integers in ≺θ\prec_\theta≺θ​-order" contains no monotone 444-term arithmetic progression (positions of a,a+r,a+2r,a+3ra,a+r,a+2r,a+3ra,a+r,a+2r,a+3r increasing, r≠0r\neq0r=0). Positions in QQQ are first occurrences. For a word QQQ let Q0Q_0Q0​ be the subsequence of even letters mapped by x↦x/2x\mapsto x/2x↦x/2, and Q1Q_1Q1​ the subsequence of odd letters mapped by x↦(x−1)/2x\mapsto (x-1)/2x↦(x−1)/2. Let θc(k,r)=θ(k+1, 2r+c)\theta_c(k,r)=\theta(k+1,\,2r+c)θc​(k,r)=θ(k+1,2r+c) for c∈{0,1}c\in\{0,1\}c∈{0,1}. Then

Q is θ-safe  ⟺  Q0 is θ0-safe, Q1 is θ1-safe, and (R) holds,Q \text{ is } \theta\text{-safe} \iff Q_0 \text{ is } \theta_0\text{-safe},\ Q_1 \text{ is } \theta_1\text{-safe, and (R) holds},Q is θ-safe⟺Q0​ is θ0​-safe, Q1​ is θ1​-safe, and (R) holds,

where the root condition (R) says: for every pair a,b∈Qa,b\in Qa,b∈Q with b−ab-ab−a odd and aaa before bbb, (i) if 2b−a∈Q2b-a\in Q2b−a∈Q occurs after bbb then 3b−2a∈Q3b-2a\in Q3b−2a∈Q occurs before 2b−a2b-a2b−a; (ii) if neither 2b−a2b-a2b−a nor 3b−2a3b-2a3b−2a lies in QQQ then bbb is odd exactly when θ(0,0)=1\theta(0,0)=1θ(0,0)=1.

This is the exact self-similarity of tree safety: all non-root constraints split into two independent problems of the same kind one binary digit lower (for the two subtrees of θ\thetaθ), and the halves interact only through the odd-difference root condition (R). It generalizes the parity decomposition for ε\varepsilonε-orders (the case θ(k,r)=εk\theta(k,r)=\varepsilon_kθ(k,r)=εk​).

Formalization note: treeLt, Safe, bitOne from Definitions.Def_Erdos195_tree/Def_Erdos195_defs; positions are List.idxOf; x / 2 is floor division, so it equals (x−1)/2(x-1)/2(x−1)/2 on odd xxx.

Preamble
import Mathlib
import Definitions.Def_Erdos195_tree
Formal statement
namespace Erdos195

theorem safe_parity_decomp (θ : ℕ → ℤ → Bool) (Q : List ℤ) :
    Safe (treeLt θ) Q ↔
      Safe (treeLt (fun k r => θ (k + 1) (2 * r)))
          ((Q.filter (fun x => decide (x % 2 = 0))).map (· / 2)) ∧
      Safe (treeLt (fun k r => θ (k + 1) (2 * r + 1)))
          ((Q.filter (fun x => decide (x % 2 = 1))).map (· / 2)) ∧
      (∀ a b : ℤ, a ∈ Q → b ∈ Q → (b - a) % 2 = 1 → Q.idxOf a < Q.idxOf b →
        (2 * b - a ∈ Q → Q.idxOf b < Q.idxOf (2 * b - a) →
          3 * b - 2 * a ∈ Q ∧ Q.idxOf (3 * b - 2 * a) < Q.idxOf (2 * b - a)) ∧
        (2 * b - a ∉ Q → 3 * b - 2 * a ∉ Q → (θ 0 0 = true ↔ b % 2 = 1))) := by sorry

end Erdos195
Source
Erdős Problem 195 (https://www.erdosproblems.com/195); tree-witness framework; self-similarity observation by GPT Sol (Oct 23 2026), general statements and Lean proofs by Grok Bot for Ethan Cheung (Oct 23 2026)

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