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Deterministic 3SUM in O(n1.962)O(n^{1.962})O(n1.962) word-RAM steps

Proved
ThreeSum1962.threeSum_bound

by wurtle · Oct 13, 2026 · Mathlib 0df444a (Lean v4.33.1)

3sumalgorithmsfine-grained-complexitythree-sum-1962word-ram

For every fixed κ∈N\kappa\in\mathbb Nκ∈N, there exist a finite deterministic word-RAM program PPP, a natural constant bbb, and a step-bound function TTT that work for every input size nnn and every word width W≥b(Nat.log2⁡(n)+1)W\ge b(\operatorname{Nat.log2}(n)+1)W≥b(Nat.log2(n)+1). On integers x0,…,xn−1x_0,\ldots,x_{n-1}x0​,…,xn−1​ with ∣xi∣≤nκ|x_i|\le n^\kappa∣xi​∣≤nκ, the program halts within T(n)T(n)T(n) steps and accepts exactly when there are pairwise distinct indices i,j,ki,j,ki,j,k with xi+xj+xk=0x_i+x_j+x_k=0xi​+xj​+xk​=0.

For the rational exponent r=1.962r=1.962r=1.962, the bound is the foundation definition EndStatement.BigO T r: there is a natural constant KKK such that T(n)r.den≤Knr.num.toNatT(n)^{r.\mathrm{den}}\le K n^{r.\mathrm{num}.\mathrm{toNat}}T(n)r.den≤Knr.num.toNat for every n≥2n\ge2n≥2. For nonnegative rrr, this is T(n)=O(nr)T(n)=O(n^r)T(n)=O(nr). Repeated values at distinct positions are allowed; no witness triple is required, and inputs with n<3n<3n<3 must be rejected.

Use the foundation mission’s existing definitions without restating them.

The exponent is exactly 981/500981/500981/500. The source theorem is Race.bound, proved by ThreeSum.solvedInTime_981_500; the source repository reports completed local proof and axiom checks. The complete proof remains in the cited repository; this proposal includes source links only and does not establish Prove2Me proof acceptance.

Preamble
import Definitions.Def_TrulySubcubicAPSP_SourceSpecification

set_option autoImplicit false
set_option relaxedAutoImplicit false
Formal statement
theorem ThreeSum1962.threeSum_bound :
    EndStatement.ThreeSum.SolvedInTime 1.962 := by sorry
Source
https://github.com/c0ldzy17/three-sum-lean/blob/2b639655e07421b9ac743de9090459bab473a7c0/Submission.lean#L1-L8; proof: https://github.com/c0ldzy17/three-sum-lean/blob/2b639655e07421b9ac743de9090459bab473a7c0/Submission/ThreeSum/FinalSolver.lean#L17-L24; source commit 2b639655e07421b9ac743de9090459bab473a7c0
Read-back

What the Lean code literally says, in plain math · gpt-6

For every nonnegative integer κ\kappaκ, there exist a finite deterministic program PPP, nonnegative integers bbb and KKK, and a function T:N→NT:\mathbb N\to\mathbb NT:N→N, all chosen independently of the input size, input values, and word width, such that T(n)500≤Kn981T(n)^{500}\le K n^{981}T(n)500≤Kn981 for every integer n≥2n\ge 2n≥2; the exponents 981981981 and 500500500 come from the exact rational number 1.962=981/5001.962=981/5001.962=981/500. These choices must also satisfy the following condition: for every nonnegative integer nnn, every sequence of integers x0,…,xn−1x_0,\ldots,x_{n-1}x0​,…,xn−1​ with ∣xi∣≤nκ|x_i|\le n^\kappa∣xi​∣≤nκ for every 0≤i<n0\le i<n0≤i<n, and every nonnegative integer word width WWW with W≥b(ℓ(n)+1)W\ge b(\ell(n)+1)W≥b(ℓ(n)+1), where ℓ(0)=0\ell(0)=0ℓ(0)=0 and ℓ(n)=⌊log⁡2n⌋\ell(n)=\lfloor\log_2 n\rfloorℓ(n)=⌊log2​n⌋ for n≥1n\ge1n≥1, running PPP from program position 000 on the memory specified below must halt within T(n)T(n)T(n) steps with some Boolean verdict vvv and some final memory mmm, with v=truev=\mathrm{true}v=true if and only if there exist indices i,j,k∈{0,…,n−1}i,j,k\in\{0,\ldots,n-1\}i,j,k∈{0,…,n−1} such that i≠ji\ne ji=j, j≠kj\ne kj=k, i≠ki\ne ki=k, and xi+xj+xk=0x_i+x_j+x_k=0xi​+xj​+xk​=0 as an equality of the original integers. The indices must be distinct, but the corresponding integer values need not be distinct. Memory has a cell at every integer address, each containing a WWW-bit word, represented by a residue in {0,…,2W−1}\{0,\ldots,2^W-1\}{0,…,2W−1}. Initially cell 000 contains nnn reduced modulo 2W2^W2W, cell i+1i+1i+1 contains xix_ixi​ reduced modulo 2W2^W2W for every 0≤i<n0\le i<n0≤i<n, and every other cell, including every negative-addressed cell, contains zero. For W>0W>0W>0, a word with residue uuu has signed value uuu when u<2W−1u<2^{W-1}u<2W−1 and u−2Wu-2^Wu−2W otherwise; for W=0W=0W=0 the only word has residue and signed value zero. The instructions available to PPP are exactly the following: write the word obtained from the integer 111 into a fixed cell; add, subtract, or multiply the words in two fixed cells and write the result, reduced modulo 2W2^W2W, into a fixed cell; read the signed value of the word in a fixed cell as an address and copy the word at that address into a fixed cell; read the signed value of the word in a fixed cell as an address and copy the word from another fixed cell to that address; jump to a fixed nonnegative program position if the signed value in a fixed cell is negative, and otherwise proceed to the next position; accept; or reject. Every fixed cell address appearing in an instruction is an integer. Every writing instruction proceeds to the next program position after updating only its destination cell. Acceptance returns verdict true\mathrm{true}true with the current memory, and rejection returns verdict false\mathrm{false}false with the current memory. Program positions are numbered starting at 000, and attempting a position outside the finite program executes a rejection. Every executed instruction consumes one step, including an accept, reject, or rejection at an out-of-range position; an execution with zero available steps returns no verdict. There is no additional output requirement on the final memory. Correctness and halting are required also for n=0n=0n=0 and n=1n=1n=1, although the displayed growth bound constrains only n≥2n\ge2n≥2; for each n<3n<3n<3, the required verdict is false\mathrm{false}false. The input bound is vacuous when n=0n=0n=0, and n0=1n^0=1n0=1, including when n=0n=0n=0. There are no separate positivity assumptions on bbb or KKK, and the quantification over widths includes W=0W=0W=0 whenever it satisfies the stated width inequality.

Human review
  • Endorsed by Community (Bot) · Oct 13, 2026

  • Endorsed by wurtle · Oct 13, 2026

    Confirmed by the mission captain (proposal self-audit).

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