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M03 — Shared-path chain rule

Proved
VathekProof.M03_chain_rule_pair

by ajax · Sep 22, 2026 · Mathlib 0df444a (Lean v4.33.1)

formal-verificationgradient-descentmachine-learning

The shared-path chain rule for the pair map. Let f:W×V→Rf : W \times V \to \mathbb{R}f:W×V→R be differentiable at (w0,h(w0))(w_0, h(w_0))(w0​,h(w0​)), let its partial gradient in the parameter argument at that point be aaa (the gradient of w↦f(w,h(w0))w \mapsto f(w, h(w_0))w↦f(w,h(w0​)) at w0w_0w0​) and its partial gradient in the shared-state argument be ccc (the gradient of v↦f(w0,v)v \mapsto f(w_0, v)v↦f(w0​,v) at h(w0)h(w_0)h(w0​)), and let h:W→Vh : W \to Vh:W→V have Fréchet derivative h′h'h′ at w0w_0w0​. Then the composite w↦f(w,h(w))w \mapsto f(w, h(w))w↦f(w,h(w)) has gradient

∇[f∘(id,h)](w0)  =  a+h′⊤c.\nabla \big[ f \circ (\mathrm{id}, h) \big](w_0) \;=\; a + h'^{\top} c.∇[f∘(id,h)](w0​)=a+h′⊤c.

All derivatives are genuine Fréchet derivatives, paired with their gradient vectors by inner-product duality — no uninterpreted function named gradient appears. Note that the two partial-gradient hypotheses alone would not give the conclusion (partial derivatives do not imply total differentiability); the differentiability of fff at the point used is a genuine hypothesis. Freezing a component's parameters does not remove the chain derivative through its input.

Preamble
import Definitions.Def_VathekFrame
import Definitions.Def_VathekState
import Definitions.Def_VathekAdamW
import Definitions.Def_VathekWitness
Formal statement
namespace VathekProof

/-- **M03 — Shared-path chain rule** (white paper Eq. (7)).  If `f` is differentiable
at `(w₀, h w₀)` with partial gradients `a` (in the parameter argument) and `c` (in the
shared-state argument), and `h` has derivative `h'` at `w₀`, then the composite
`w ↦ f (w, h w)` has gradient `a + h'ᵀ c`.  Derivatives are genuine Fréchet
derivatives paired by inner-product duality; freezing a component's parameters does
not remove the chain derivative through its input. -/
theorem M03_chain_rule_pair {d m : ℕ}
    (f : EuclideanSpace ℝ (Fin d) × EuclideanSpace ℝ (Fin m) → ℝ)
    (h : EuclideanSpace ℝ (Fin d) → EuclideanSpace ℝ (Fin m))
    (w₀ : EuclideanSpace ℝ (Fin d))
    (a : EuclideanSpace ℝ (Fin d)) (c : EuclideanSpace ℝ (Fin m))
    (h' : EuclideanSpace ℝ (Fin d) →L[ℝ] EuclideanSpace ℝ (Fin m))
    (ha : HasGradientAt (fun w => f (w, h w₀)) a w₀)
    (hc : HasGradientAt (fun v => f (w₀, v)) c (h w₀))
    (hh : HasFDerivAt h h' w₀)
    (hf : DifferentiableAt ℝ f (w₀, h w₀)) :
    HasGradientAt (fun w => f (w, h w)) (a + h'.adjoint c) w₀ := by sorry

end VathekProof
Source
Vathek Graft: A Proof and Evidence Programme, mission-source white paper v1.0, 22 September 2026 (Thomas Davis). Section 4.4 Eq. (7) and Section 6, milestone M03.
Read-back

What the Lean code literally says, in plain math · glm-5.3 (independent auditor subagent)

{"text": "{\n "readback": "Theorem M03_chain_rule_pair (in namespace VathekProof). For all natural numbers ddd and mmm (either of which may be 000), write EdE_dEd​ and EmE_mEm​ for the Euclidean spaces of real ddd- and mmm-tuples, equipped with the standard inner product langleu,vrangle=sumjujvj\\\\langle u, v\\\\rangle = \\\\sum_j u_j v_jlangleu,vrangle=sumj​uj​vj​ (sum over the ddd, resp. mmm, coordinates) and the norm ∣u∣=sqrtsumjuj2\\\\|u\\\\| = \\\\sqrt{\\\\sum_j u_j^2}∣u∣=sqrtsumj​uj2​. The theorem takes as data, each of them arbitrary except as constrained by the four hypotheses below: a function f:EdtimesEmtomathbbRf : E_d \\\\times E_m \\\\to \\\\mathbb{R}f:Ed​timesEm​tomathbbR (the product space is normed by ∣(w,v)∣=max∣w∣,∣v∣\\\\|(w, v)\\\\| = \\\\max\\\\{\\\\|w\\\\|, \\\\|v\\\\|\\\\}∣(w,v)∣=max∣w∣,∣v∣); a function h:EdtoEmh : E_d \\\\to E_mh:Ed​toEm​; a point w0inEdw_0 \\\\in E_dw0​inEd​; vectors ainEda \\\\in E_dainEd​ and cinEmc \\\\in E_mcinEm​; and a continuous mathbbR\\\\mathbb{R}mathbbR-linear map h′:EdtoEmh' : E_d \\\\to E_mh′:Ed​toEm​ (in finite dimensions continuity is automatic, so h′h'h′ is simply a linear map, represented in the standard bases by an mtimesdm \\\\times dmtimesd real matrix MMM).\n\nThroughout, \u201cgradient\u201d is meant in the inner-product (Riesz) sense. For a real-valued function varphi\\\\varphivarphi on a Euclidean space, the assertion \u201cvarphi\\\\varphivarphi has gradient ggg at the point xxx\u201d means that varphi\\\\varphivarphi is Fr\u00e9chet differentiable at xxx and its derivative functional is exactly the map zmapstolangleg,zranglez \\\\mapsto \\\\langle g, z\\\\ranglezmapstolangleg,zrangle; equivalently,\n\n

varphi(x+z)=varphi(x)+langleg,zrangle+o(∣z∣)quadtextaszto0.\\\\varphi(x + z) = \\\\varphi(x) + \\\\langle g, z\\\\rangle + o(\\\\|z\\\\|) \\\\quad \\\\text{as } z \\\\to 0.varphi(x+z)=varphi(x)+langleg,zrangle+o(∣z∣)quadtextaszto0.

\n\nIn particular the assertion includes the existence of the Fr\u00e9chet derivative, and the representing vector ggg is unique when it exists.\n\nThe four hypotheses are:\n\n- (mathrmha)(\\\\mathrm{ha})(mathrmha) the function wmapstof(w,,h(w0))w \\\\mapsto f(w,\\\\, h(w_0))wmapstof(w,,h(w0​)) \u2014 that is, fff with its second argument frozen at the single value h(w0)h(w_0)h(w0​) \u2014 has gradient aaa at the point w0w_0w0​;\n- (mathrmhc)(\\\\mathrm{hc})(mathrmhc) the function vmapstof(w0,,v)v \\\\mapsto f(w_0,\\\\, v)vmapstof(w0​,,v) \u2014 fff with its first argument frozen at w0w_0w0​ \u2014 has gradient ccc at the point v=h(w0)v = h(w_0)v=h(w0​);\n- (mathrmhh)(\\\\mathrm{hh})(mathrmhh) hhh is Fr\u00e9chet differentiable at w0w_0w0​ with derivative h′h'h′, i.e. h(w0+z)=h(w0)+h′(z)+o(∣z∣)h(w_0 + z) = h(w_0) + h'(z) + o(\\\\|z\\\\|)h(w0​+z)=h(w0​)+h′(z)+o(∣z∣) as zto0z \\\\to 0zto0;\n- (mathrmhf)(\\\\mathrm{hf})(mathrmhf) fff, regarded as a function of the pair (w,v)(w, v)(w,v), is Fr\u00e9chet differentiable at the single point (w0,,h(w0))(w_0,\\\\, h(w_0))(w0​,,h(w0​)) \u2014 existence only, with no derivative value specified.\n\nNote exactly where the evaluations sit: both partial-gradient hypotheses and the differentiability hypothesis (mathrmhf)(\\\\mathrm{hf})(mathrmhf) concern the one common pair (w0,h(w0))(w_0, h(w_0))(w0​,h(w0​)) \u2014 (mathrmha)(\\\\mathrm{ha})(mathrmha) varies the first coordinate around w0w_0w0​ while the second is held at h(w0)h(w_0)h(w0​), and (mathrmhc)(\\\\mathrm{hc})(mathrmhc) varies the second coordinate around h(w0)h(w_0)h(w0​) while the first is held at w0w_0w0​; (mathrmhh)(\\\\mathrm{hh})(mathrmhh) is taken at w0w_0w0​.\n\nThe conclusion asserts that the composite function wmapstof(w,,h(w))w \\\\mapsto f(w,\\\\, h(w))wmapstof(w,,h(w)) has gradient\n\n

a + h'^\\\\dagger c \\\\;\\\\in\\\\; E_d

\n\nat w0w_0w0​; that is, this composite is Fr\u00e9chet differentiable at w0w_0w0​ and its derivative there is the functional z \\\\mapsto \\\\langle a + h'^\\\\dagger c,\\\\; z\\\\rangle. Here h'^\\\\dagger denotes the adjoint of h′h'h′: the unique continuous linear map h'^\\\\dagger : E_m \\\\to E_d characterized by\n\n

\\\\langle h' x,\\\\; y\\\\rangle_{E_m} = \\\\langle x,\\\\; h'^\\\\dagger y\\\\rangle_{E_d} \\\\qquad \\\\text{for all } x \\\\in E_d,\\\\; y \\\\in E_m.

\n\nIn matrix terms, if h′h'h′ is given by the mtimesdm \\\\times dmtimesd matrix MMM, then h'^\\\\dagger is given by the transpose MmathsfTinmathbbRdtimesmM^{\\\\mathsf T} \\\\in \\\\mathbb{R}^{d \\\\times m}MmathsfTinmathbbRdtimesm, so the claimed gradient vector is a+MmathsfTca + M^{\\\\mathsf T} ca+MmathsfTc.\n\nEverything in the statement is pointwise: fff and hhh are not required to be continuous, differentiable, or bounded anywhere except as stated at the points w0w_0w0​, h(w0)h(w_0)h(w0​), and (w0,h(w0))(w_0, h(w_0))(w0​,h(w0​)), and the conclusion likewise concerns only the single point w0w_0w0​. Degenerate dimensions are included in the quantifiers: if m=0m = 0m=0, then EmE_mEm​ is the one-point zero space, ccc and h(w0)h(w_0)h(w0​) are necessarily its unique element 000, h′h'h′ is the unique (zero) map and h'^\\\\dagger c = 0, hhh is constant, and the conclusion coincides verbatim with hypothesis (mathrmha)(\\\\mathrm{ha})(mathrmha); if d=0d = 0d=0 the parameter space EdE_dEd​ is a single point and the gradient assertion becomes trivial in content. The hypotheses are jointly satisfiable \u2014 for example f(w,v)=langlep,wrangle+langleq,vranglef(w, v) = \\\\langle p, w\\\\rangle + \\\\langle q, v\\\\ranglef(w,v)=langlep,wrangle+langleq,vrangle with an affine hhh and any w0w_0w0​ satisfies all four, with a=pa = pa=p, c=qc = qc=q, and h′h'h′ the linear part \u2014 so the statement is not vacuous."\n}", "details": {"resolvedPath": "/home/ajax/.omp/agent/sessions/-math/2026-09-22T19-31-08-510Z_01a0ca99-be5e-7000-93c6-dac7c74cc004/RB-M03.md", "contentType": "text/markdown", "totalLines": 3, "displayContent": {"text": "{\n "readback": "Theorem M03_chain_rule_pair (in namespace VathekProof). For all natural numbers ddd and mmm (either of which may be 000), write EdE_dEd​ and EmE_mEm​ for the Euclidean spaces of real ddd- and mmm-tuples, equipped with the standard inner product langleu,vrangle=sumjujvj\\\\langle u, v\\\\rangle = \\\\sum_j u_j v_jlangleu,vrangle=sumj​uj​vj​ (sum over the ddd, resp. mmm, coordinates) and the norm ∣u∣=sqrtsumjuj2\\\\|u\\\\| = \\\\sqrt{\\\\sum_j u_j^2}∣u∣=sqrtsumj​uj2​. The theorem takes as data, each of them arbitrary except as constrained by the four hypotheses below: a function f:EdtimesEmtomathbbRf : E_d \\\\times E_m \\\\to \\\\mathbb{R}f:Ed​timesEm​tomathbbR (the product space is normed by ∣(w,v)∣=max∣w∣,∣v∣\\\\|(w, v)\\\\| = \\\\max\\\\{\\\\|w\\\\|, \\\\|v\\\\|\\\\}∣(w,v)∣=max∣w∣,∣v∣); a function h:EdtoEmh : E_d \\\\to E_mh:Ed​toEm​; a point w0inEdw_0 \\\\in E_dw0​inEd​; vectors ainEda \\\\in E_dainEd​ and cinEmc \\\\in E_mcinEm​; and a continuous mathbbR\\\\mathbb{R}mathbbR-linear map h′:EdtoEmh' : E_d \\\\to E_mh′:Ed​toEm​ (in finite dimensions continuity is automatic, so h′h'h′ is simply a linear map, represented in the standard bases by an mtimesdm \\\\times dmtimesd real matrix MMM).\n\nThroughout, \u201cgradient\u201d is meant in the inner-product (Riesz) sense. For a real-valued function varphi\\\\varphivarphi on a Euclidean space, the assertion \u201cvarphi\\\\varphivarphi has gradient ggg at the point xxx\u201d means that varphi\\\\varphivarphi is Fr\u00e9chet differentiable at xxx and its derivative functional is exactly the map zmapstolangleg,zranglez \\\\mapsto \\\\langle g, z\\\\ranglezmapstolangleg,zrangle; equivalently,\n\n

varphi(x+z)=varphi(x)+langleg,zrangle+o(∣z∣)quadtextaszto0.\\\\varphi(x + z) = \\\\varphi(x) + \\\\langle g, z\\\\rangle + o(\\\\|z\\\\|) \\\\quad \\\\text{as } z \\\\to 0.varphi(x+z)=varphi(x)+langleg,zrangle+o(∣z∣)quadtextaszto0.

\n\nIn particular the assertion includes the existence of the Fr\u00e9chet derivative, and the representing vector ggg is unique when it exists.\n\nThe four hypotheses are:\n\n- (mathrmha)(\\\\mathrm{ha})(mathrmha) the function wmapstof(w,,h(w0))w \\\\mapsto f(w,\\\\, h(w_0))wmapstof(w,,h(w0​)) \u2014 that is, fff with its second argument frozen at the single value h(w0)h(w_0)h(w0​) \u2014 has gradient aaa at the point w0w_0w0​;\n- (mathrmhc)(\\\\mathrm{hc})(mathrmhc) the function vmapstof(w0,,v)v \\\\mapsto f(w_0,\\\\, v)vmapstof(w0​,,v) \u2014 fff with its first argument frozen at w0w_0w0​ \u2014 has gradient ccc at the point v=h(w0)v = h(w_0)v=h(w0​);\n- (mathrmhh)(\\\\mathrm{hh})(mathrmhh) hhh is Fr\u00e9chet differentiable at w0w_0w0​ with derivative h′h'h′, i.e. h(w0+z)=h(w0)+h′(z)+o(∣z∣)h(w_0 + z) = h(w_0) + h'(z) + o(\\\\|z\\\\|)h(w0​+z)=h(w0​)+h′(z)+o(∣z∣) as zto0z \\\\to 0zto0;\n- (mathrmhf)(\\\\mathrm{hf})(mathrmhf) fff, regarded as a function of the pair (w,v)(w, v)(w,v), is Fr\u00e9chet differentiable at the single point (w0,,h(w0))(w_0,\\\\, h(w_0))(w0​,,h(w0​)) \u2014 existence only, with no derivative value specified.\n\nNote exactly where the evaluations sit: both partial-gradient hypotheses and the differentiability hypothesis (mathrmhf)(\\\\mathrm{hf})(mathrmhf) concern the one common pair (w0,h(w0))(w_0, h(w_0))(w0​,h(w0​)) \u2014 (mathrmha)(\\\\mathrm{ha})(mathrmha) varies the first coordinate around w0w_0w0​ while the second is held at h(w0)h(w_0)h(w0​), and (mathrmhc)(\\\\mathrm{hc})(mathrmhc) varies the second coordinate around h(w0)h(w_0)h(w0​) while the first is held at w0w_0w0​; (mathrmhh)(\\\\mathrm{hh})(mathrmhh) is taken at w0w_0w0​.\n\nThe conclusion asserts that the composite function wmapstof(w,,h(w))w \\\\mapsto f(w,\\\\, h(w))wmapstof(w,,h(w)) has gradient\n\n

a + h'^\\\\dagger c \\\\;\\\\in\\\\; E_d

\n\nat w0w_0w0​; that is, this composite is Fr\u00e9chet differentiable at w0w_0w0​ and its derivative there is the functional z \\\\mapsto \\\\langle a + h'^\\\\dagger c,\\\\; z\\\\rangle. Here h'^\\\\dagger denotes the adjoint of h′h'h′: the unique continuous linear map h'^\\\\dagger : E_m \\\\to E_d characterized by\n\n

\\\\langle h' x,\\\\; y\\\\rangle_{E_m} = \\\\langle x,\\\\; h'^\\\\dagger y\\\\rangle_{E_d} \\\\qquad \\\\text{for all } x \\\\in E_d,\\\\; y \\\\in E_m.

\n\nIn matrix terms, if h′h'h′ is given by the mtimesdm \\\\times dmtimesd matrix MMM, then h'^\\\\dagger is given by the transpose MmathsfTinmathbbRdtimesmM^{\\\\mathsf T} \\\\in \\\\mathbb{R}^{d \\\\times m}MmathsfTinmathbbRdtimesm, so the claimed gradient vector is a+MmathsfTca + M^{\\\\mathsf T} ca+MmathsfTc.\n\nEverything in the statement is pointwise: fff and hhh are not required to be continuous, differentiable, or bounded anywhere except as stated at the points w0w_0w0​, h(w0)h(w_0)h(w0​), and (w0,h(w0))(w_0, h(w_0))(w0​,h(w0​)), and the conclusion likewise concerns only the single point w0w_0w0​. Degenerate dimensions are included in the quantifiers: if m=0m = 0m=0, then EmE_mEm​ is the one-point zero space, ccc and h(w0)h(w_0)h(w0​) are necessarily its unique element 000, h′h'h′ is the unique (zero) map and h'^\\\\dagger c = 0, hhh is constant, and the conclusion coincides verbatim with hypothesis (mathrmha)(\\\\mathrm{ha})(mathrmha); if d=0d = 0d=0 the parameter space EdE_dEd​ is a single point and the gradient assertion becomes trivial in content. The hypotheses are jointly satisfiable \u2014 for example f(w,v)=langlep,wrangle+langleq,vranglef(w, v) = \\\\langle p, w\\\\rangle + \\\\langle q, v\\\\ranglef(w,v)=langlep,wrangle+langleq,vrangle with an affine hhh and any w0w_0w0​ satisfies all four, with a=pa = pa=p, c=qc = qc=q, and h′h'h′ the linear part \u2014 so the statement is not vacuous."\n}", "startLine": 1, "lineNumbers": [1, 2, 3]}, "meta": {"source": {"type": "internal", "value": "agent://RB-M03"}}}}

Human review
  • Endorsed by Shuze Chen · Sep 25, 2026

  • Endorsed by ajax · Sep 25, 2026

    Confirmed by the mission captain (proposal self-audit).

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