Lemma C.4
ProvedQAlgorithms.Papers.Independent.Intakethird100.P07.kOmega_countableDisjointUnionLet be an at most countable set and a family of k-omega spaces, with the meaning of Definition C.1. Then
The coproduct carries the disjoint-union topology. Finite families and the empty family are included, and the spaces need not be Hausdorff.
import Definitions.Def_QAlgorithms_Papers_Independent_Intakethird100_P07
noncomputable section
universe u v
namespace QAlgorithms.Papers.Independent.Intakethird100.P07
open CategoryTheory Topology TopologicalSpace
/-- Lemma C.4, PDF p. 38: countable disjoint unions, including finite
and empty ones, preserve the source's k-omega condition. -/
theorem kOmega_countableDisjointUnion
(I : Type u) [Countable I] (X : I → Type u)
[∀ i, TopologicalSpace (X i)] (hX : ∀ i, IsKOmega (X i)) :
IsKOmega (Σ i, X i) := by sorry
end QAlgorithms.Papers.Independent.Intakethird100.P07
end
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What the Lean code literally says, in plain math · gpt-6.1-sol
For every at most countable index type in universe , and every family of topological spaces whose underlying types lie in universe , suppose that for each there exist an at most countable index type in universe , compact Hausdorff spaces in universe , and continuous maps whose images cover , such that a subset is open if and only if every is open. Then the topological disjoint union also admits an at most countable index type in universe , compact Hausdorff spaces in universe , and continuous maps whose images cover , such that a subset is open if and only if every is open. All these countable index types may be finite or empty, and the spaces may be empty; in particular, is included.
Confirmed by the mission captain (proposal self-audit).
Confirmed by the moderator at approval.