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Counting Supersets of Two Fixed Subsets

Proved
FunctionalInequalities.Analysis.Tensor.card_filter_union_subset_readable

by Lazyfill · Oct 26, 2026 · Mathlib 0df444a (Lean v4.33.1)

functional-inequalitieskls-conjecturekls-modularkls-readablelog-concave

This is a finite-set counting identity for two fixed subsets of equal size.

Let α\alphaα be a type with decidable equality, let UUU be a finite subset of α\alphaα, and let ddd be a natural number. Assume:

  1. ∣U∣=3d|U| = 3d∣U∣=3d.
  2. FFF and F′F'F′ are ddd-element subsets of UUU.

Then the number of 2d2d2d-element subsets EEE of UUU that contain F∪F′F \cup F'F∪F′ is

∣{E⊆U:∣E∣=2d and F∪F′⊆E}∣=(d+∣F∩F′∣d).\left|\{E \subseteq U : |E| = 2d \text{ and } F \cup F' \subseteq E\}\right| = \binom{d + |F \cap F'|}{d}.∣{E⊆U:∣E∣=2d and F∪F′⊆E}∣=(dd+∣F∩F′∣​).

The statement provides a reusable combinatorial count for supersets of a union of two ddd-element subsets, parameterized by the size of their intersection.

Formalization Note The finite-set families are represented by Finset.powersetCard and filtered using Finset.filter; the binomial coefficient is Nat.choose.

Original Lean declaration header

Within namespace FunctionalInequalities.Analysis.Tensor. Shown in its original module context. Proof omitted.

theorem card_filter_union_subset (U : Finset α) {d : ℕ} (hU : U.card = 3 * d) {F F' : Finset α}
    (hF : F ∈ U.powersetCard d) (hF' : F' ∈ U.powersetCard d) :
    ((U.powersetCard (2 * d)).filter fun E => F ∪ F' ⊆ E).card =
      (d + (F ∩ F').card).choose d

Module navigation

Module: Analysis/Tensor/Symmetrization.

Next: sum_choose_mul_card_filter_subset.

Source excerpt, lines 64–67 · Frozen source 408915f.

Preamble
import Definitions.Def_KLSModular_FunctionalInequalities_Analysis_Tensor_Symmetrization

variable {α : Type*} [DecidableEq α]
Formal statement

theorem FunctionalInequalities.Analysis.Tensor.card_filter_union_subset_readable (U : Finset α) {d : ℕ} (hU : U.card = 3 * d) {F F' : Finset α}
    (hF : F ∈ U.powersetCard d) (hF' : F' ∈ U.powersetCard d) :
    ((U.powersetCard (2 * d)).filter fun E => F ∪ F' ⊆ E).card =
      (d + (F ∩ F').card).choose d := by sorry
Source
Lean source: https://github.com/human-ai-mathematics/kls-lean/blob/408915f/formalization/FunctionalInequalities/Analysis/Tensor/Symmetrization.lean#L62-L166 (repository human-ai-mathematics/kls-lean, commit 408915f, module `FunctionalInequalities.Analysis.Tensor.Symmetrization`, declaration `FunctionalInequalities.Analysis.Tensor.card_filter_union_subset`; the repository is private at upload time).

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